Pythagorean Theorem Proof

Pull up a chair, and don’t make a move! We’ve got something we really must prove, ‘Bout sides of a right triangle, num’bring three. You’ve somewhere to be? I won’t hear your plea! A plus B, squared, as in the picture I drew (A+B)^2= C^2 + 4AB/2 Equals C squared plus 4 times AB over two. Next, smartly observe that four, two divides, (A+B)^2= C^2 + 2AB And promptly subtract 2AB from both sides. (A+B)^2–2AB= C^2+2AB-2AB Expand A plus B, squared; and then simplify. A^2+B^2 +2AB–2AB= C^2 You’ve just used your math to well justify A^2 + B^2 = C^2 And prove what Pythagoras wisely declared - A squared plus B squared is exactly C squared.